Integrand size = 34, antiderivative size = 290 \[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=-\frac {2 a^4 \left (A \left (64+60 m+19 m^2+2 m^3\right )-i B \left (67+60 m+19 m^2+2 m^3\right )\right ) \tan ^{1+m}(c+d x)}{d (1+m) (2+m) (3+m) (4+m)}+\frac {8 a^4 (A-i B) \operatorname {Hypergeometric2F1}(1,1+m,2+m,i \tan (c+d x)) \tan ^{1+m}(c+d x)}{d (1+m)}+\frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}-\frac {2 \left (A (4+m)^2-i B \left (19+8 m+m^2\right )\right ) \tan ^{1+m}(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{d (2+m) (3+m) (4+m)} \]
[Out]
Time = 1.20 (sec) , antiderivative size = 290, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.147, Rules used = {3675, 3673, 3618, 12, 66} \[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\frac {8 a^4 (A-i B) \tan ^{m+1}(c+d x) \operatorname {Hypergeometric2F1}(1,m+1,m+2,i \tan (c+d x))}{d (m+1)}-\frac {2 \left (A (m+4)^2-i B \left (m^2+8 m+19\right )\right ) \left (a^4+i a^4 \tan (c+d x)\right ) \tan ^{m+1}(c+d x)}{d (m+2) (m+3) (m+4)}-\frac {2 a^4 \left (A \left (2 m^3+19 m^2+60 m+64\right )-i B \left (2 m^3+19 m^2+60 m+67\right )\right ) \tan ^{m+1}(c+d x)}{d (m+1) (m+2) (m+3) (m+4)}-\frac {(A (m+4)-i B (m+7)) \left (a^2+i a^2 \tan (c+d x)\right )^2 \tan ^{m+1}(c+d x)}{d (m+3) (m+4)}+\frac {i a B (a+i a \tan (c+d x))^3 \tan ^{m+1}(c+d x)}{d (m+4)} \]
[In]
[Out]
Rule 12
Rule 66
Rule 3618
Rule 3673
Rule 3675
Rubi steps \begin{align*} \text {integral}& = \frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}+\frac {\int \tan ^m(c+d x) (a+i a \tan (c+d x))^3 (-a (i B (1+m)-A (4+m))+a (i A (4+m)+B (7+m)) \tan (c+d x)) \, dx}{4+m} \\ & = \frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}+\frac {\int \tan ^m(c+d x) (a+i a \tan (c+d x))^2 \left (-2 a^2 \left (i B \left (5+6 m+m^2\right )-A \left (8+6 m+m^2\right )\right )+2 a^2 \left (i A (4+m)^2+B \left (19+8 m+m^2\right )\right ) \tan (c+d x)\right ) \, dx}{12+7 m+m^2} \\ & = \frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}-\frac {2 \left (A (4+m)^2-i B \left (19+8 m+m^2\right )\right ) \tan ^{1+m}(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{d (2+m) \left (12+7 m+m^2\right )}+\frac {\int \tan ^m(c+d x) (a+i a \tan (c+d x)) \left (-2 a^3 \left (i B \left (29+44 m+17 m^2+2 m^3\right )-A \left (32+44 m+17 m^2+2 m^3\right )\right )+2 a^3 \left (i A \left (64+60 m+19 m^2+2 m^3\right )+B \left (67+60 m+19 m^2+2 m^3\right )\right ) \tan (c+d x)\right ) \, dx}{24+26 m+9 m^2+m^3} \\ & = -\frac {2 a^4 \left (A \left (64+60 m+19 m^2+2 m^3\right )-i B \left (67+60 m+19 m^2+2 m^3\right )\right ) \tan ^{1+m}(c+d x)}{d (1+m) \left (24+26 m+9 m^2+m^3\right )}+\frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}-\frac {2 \left (A (4+m)^2-i B \left (19+8 m+m^2\right )\right ) \tan ^{1+m}(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{d (2+m) \left (12+7 m+m^2\right )}+\frac {\int \tan ^m(c+d x) \left (8 a^4 (A-i B) (2+m) (3+m) (4+m)+8 a^4 (i A+B) (2+m) (3+m) (4+m) \tan (c+d x)\right ) \, dx}{24+26 m+9 m^2+m^3} \\ & = -\frac {2 a^4 \left (A \left (64+60 m+19 m^2+2 m^3\right )-i B \left (67+60 m+19 m^2+2 m^3\right )\right ) \tan ^{1+m}(c+d x)}{d (1+m) \left (24+26 m+9 m^2+m^3\right )}+\frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}-\frac {2 \left (A (4+m)^2-i B \left (19+8 m+m^2\right )\right ) \tan ^{1+m}(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{d (2+m) \left (12+7 m+m^2\right )}+\frac {\left (64 i a^8 (A-i B)^2 (2+m) (3+m) (4+m)\right ) \text {Subst}\left (\int \frac {8^{-m} \left (\frac {x}{a^4 (i A+B) (2+m) (3+m) (4+m)}\right )^m}{64 a^8 (i A+B)^2 (2+m)^2 (3+m)^2 (4+m)^2+8 a^4 (A-i B) (2+m) (3+m) (4+m) x} \, dx,x,8 a^4 (i A+B) (2+m) (3+m) (4+m) \tan (c+d x)\right )}{d} \\ & = -\frac {2 a^4 \left (A \left (64+60 m+19 m^2+2 m^3\right )-i B \left (67+60 m+19 m^2+2 m^3\right )\right ) \tan ^{1+m}(c+d x)}{d (1+m) \left (24+26 m+9 m^2+m^3\right )}+\frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}-\frac {2 \left (A (4+m)^2-i B \left (19+8 m+m^2\right )\right ) \tan ^{1+m}(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{d (2+m) \left (12+7 m+m^2\right )}+\frac {\left (i 8^{2-m} a^8 (A-i B)^2 (2+m) (3+m) (4+m)\right ) \text {Subst}\left (\int \frac {\left (\frac {x}{a^4 (i A+B) (2+m) (3+m) (4+m)}\right )^m}{64 a^8 (i A+B)^2 (2+m)^2 (3+m)^2 (4+m)^2+8 a^4 (A-i B) (2+m) (3+m) (4+m) x} \, dx,x,8 a^4 (i A+B) (2+m) (3+m) (4+m) \tan (c+d x)\right )}{d} \\ & = -\frac {2 a^4 \left (A \left (64+60 m+19 m^2+2 m^3\right )-i B \left (67+60 m+19 m^2+2 m^3\right )\right ) \tan ^{1+m}(c+d x)}{d (1+m) \left (24+26 m+9 m^2+m^3\right )}+\frac {8 a^4 (A-i B) \operatorname {Hypergeometric2F1}(1,1+m,2+m,i \tan (c+d x)) \tan ^{1+m}(c+d x)}{d (1+m)}+\frac {i a B \tan ^{1+m}(c+d x) (a+i a \tan (c+d x))^3}{d (4+m)}-\frac {(A (4+m)-i B (7+m)) \tan ^{1+m}(c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{d (3+m) (4+m)}-\frac {2 \left (A (4+m)^2-i B \left (19+8 m+m^2\right )\right ) \tan ^{1+m}(c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{d (2+m) \left (12+7 m+m^2\right )} \\ \end{align*}
Time = 3.10 (sec) , antiderivative size = 173, normalized size of antiderivative = 0.60 \[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\frac {a^4 \tan ^{1+m}(c+d x) \left (\frac {(A-i B) \left (-7 \left (6+5 m+m^2\right )+8 \left (6+5 m+m^2\right ) \operatorname {Hypergeometric2F1}(1,1+m,2+m,i \tan (c+d x))-4 i \left (3+4 m+m^2\right ) \tan (c+d x)+\left (2+3 m+m^2\right ) \tan ^2(c+d x)\right )}{(1+m) (2+m) (3+m)}+i B \left (\frac {1}{1+m}+\frac {3 i \tan (c+d x)}{2+m}-\frac {3 \tan ^2(c+d x)}{3+m}-\frac {i \tan ^3(c+d x)}{4+m}\right )\right )}{d} \]
[In]
[Out]
\[\int \left (\tan ^{m}\left (d x +c \right )\right ) \left (a +i a \tan \left (d x +c \right )\right )^{4} \left (A +B \tan \left (d x +c \right )\right )d x\]
[In]
[Out]
\[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\int { {\left (B \tan \left (d x + c\right ) + A\right )} {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{4} \tan \left (d x + c\right )^{m} \,d x } \]
[In]
[Out]
\[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=a^{4} \left (\int A \tan ^{m}{\left (c + d x \right )}\, dx + \int \left (- 6 A \tan ^{2}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\right )\, dx + \int A \tan ^{4}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\, dx + \int B \tan {\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\, dx + \int \left (- 6 B \tan ^{3}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\right )\, dx + \int B \tan ^{5}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\, dx + \int 4 i A \tan {\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\, dx + \int \left (- 4 i A \tan ^{3}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\right )\, dx + \int 4 i B \tan ^{2}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\, dx + \int \left (- 4 i B \tan ^{4}{\left (c + d x \right )} \tan ^{m}{\left (c + d x \right )}\right )\, dx\right ) \]
[In]
[Out]
\[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\int { {\left (B \tan \left (d x + c\right ) + A\right )} {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{4} \tan \left (d x + c\right )^{m} \,d x } \]
[In]
[Out]
\[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\int { {\left (B \tan \left (d x + c\right ) + A\right )} {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{4} \tan \left (d x + c\right )^{m} \,d x } \]
[In]
[Out]
Timed out. \[ \int \tan ^m(c+d x) (a+i a \tan (c+d x))^4 (A+B \tan (c+d x)) \, dx=\int {\mathrm {tan}\left (c+d\,x\right )}^m\,\left (A+B\,\mathrm {tan}\left (c+d\,x\right )\right )\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^4 \,d x \]
[In]
[Out]